Silkworth, Pennsylvania

Silkworth, Pennsylvania
Census-designated place
Silkworth, Pennsylvania

Location within the state of Pennsylvania

Coordinates: 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611Coordinates: 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611
Country United States
State Pennsylvania
County Luzerne
Township Lehman Township
Area
  Total 3.8 sq mi (9.9 km2)
  Land 3.4 sq mi (8.8 km2)
  Water 0.4 sq mi (1.1 km2)
Population (2010)
  Total 820
  Density 210/sq mi (83/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
Area code(s) 570

Silkworth is a census-designated place (CDP) in Lehman Township, Luzerne County, Pennsylvania, United States. The population was 820 at the 2010 census.[1]

Geography

Silkworth is located at 41°16′20″N 76°5′10″W / 41.27222°N 76.08611°W / 41.27222; -76.08611,[2] along Pennsylvania Route 29 on the west shore of Lake Silkworth, about 10 miles (16 km) northwest of the city of Nanticoke.

According to the United States Census Bureau, the CDP has a total area of 3.8 square miles (9.9 km2), of which 3.4 square miles (8.8 km2) is land and 0.42 square miles (1.1 km2), or 11.0%, is water.[3]

References


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