United States presidential election in Indiana, 1996

United States presidential election in Indiana, 1996
Indiana
November 5, 1996

 
Nominee Bob Dole Bill Clinton Ross Perot
Party Republican Democratic Reform
Home state Kansas Arkansas Texas
Running mate Jack Kemp Al Gore Patrick Choate
Electoral vote 12 0 0
Popular vote 1,006,693 887,424 224,299
Percentage 47.1% 41.6% 10.5%

County Results
  Clinton—80-90%
  Clinton—70-80%
  Clinton—60-70%
  Clinton—50-60%
  Dole—50-60%
  Dole—60-70%
  Dole—80-90%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Indiana took place on November 5, 1996 throughout all 50 states and D.C.. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana was won by Senator Bob Dole (R-KS). The presidential contest in Indiana was not a surprise, with Dole winning 47.13% to 41.55% over President Bill Clinton (D) by a margin of 5.58%.[1] Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with a significant 10.50% of the popular vote in Indiana.[2] Indiana would stay a Republican state until 2008, in which Barack Obama won by a close margin, the first Democratic victory in Indiana since 1964.

Results

United States presidential election in Indiana, 1996[3]
Party Candidate Running mate Votes Percentage Electoral votes
Republican Bob Dole Jack Kemp 1,006,693 47.13% 12
Democratic Bill Clinton Al Gore 887,424 41.55% 0
Reform Ross Perot Patrick Choate 224,299 10.50% 0
Libertarian Harry Browne Jo Jorgensen 15,632 0.73% 0
Totals 2,135,842 100.00% 12

References

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