United States presidential election in the District of Columbia, 1996

United States presidential election in the District of Columbia, 1996
Washington, D.C.
November 5, 1996
 
Nominee Bill Clinton Bob Dole
Party Democratic Republican
Home state Arkansas Kansas
Running mate Al Gore Jack Kemp
Electoral vote 3 0
Popular vote 158,220 17,339
Percentage 85.19% 9.34%
President before election

Bill Clinton
Democratic

 Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in the District of Columbia took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Washington, D.C. was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 85.19% to 9.34% by a margin of 75.85%. Political activist Ralph Nader (Green Party) finished in third with 2.57% of the popular vote, and businessman Ross Perot (Reform Party) finished in fourth with 1.94%.[1]

Results

United States presidential election in Washington, D. C., 1996
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 158,220 85.19% 3
Republican Bob Dole Jack Kemp 17,339 9.34% 0
Green Ralph Nader Winona LaDuke 4,780 2.57% 0
Reform Ross Perot Patrick Choate 3,611 1.94% 0
No party Write-in 648 0.35% 0
Libertarian Harry Browne Jo Jorgensen 588 0.32% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 283 0.15% 0
Socialist Workers Party James Harris Laura Garza 257 0.14% 0

References

  1. ↑ Dave Leip's Atlas of United States Presidential Election Results - 1996 Washington, D. C. Results
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