United States presidential election in Virginia, 1892

United States presidential election in Virginia, 1892
Virginia
November 8, 1892

 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote 12 0
Popular vote 164,136 113,098
Percentage 56.17% 38.70%

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Virginia took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic candidate, former President Grover Cleveland over the Republican candidate, incumbent President Benjamin Harrison. Cleveland won the state by a margin of 17.46%.

Results

United States presidential election in Virginia, 1892[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 164,136 56.17% 12
Republican Benjamin Harrison (inc.) 113,098 38.70% 0
Populist James B. Weaver 12,275 4.20% 0
Prohibition John Bidwell 2,729 0.93% 0
Totals 292,238 100.0% 12

References

  1. "1892 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.
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