United States presidential election in New Hampshire, 1836
Main article: United States presidential election, 1836
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| Elections in New Hampshire |
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The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%.
Results
| United States presidential election in New Hampshire, 1836[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 18,697 | 75.01% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | Francis Granger of New York | 6,228 | 24.99% | 0 | 0.00% | ||
| Total | 24,925 | 100.00% | 7 | 100.00% | ||||
References
- ↑ "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.
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| General articles |
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| Local results | ||
| Other 1836 elections | ||
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