United States presidential election in Missouri, 1860

United States presidential election in Missouri, 1860
Missouri
November 2, 1860
 
Nominee Stephen A. Douglas John Bell John C. Breckinridge
Party Democratic Constitutional Union Southern Democratic
Home state Illinois Tennessee Kentucky
Running mate Herschel Vespasian Johnson Edward Everett Joseph Lane
Electoral vote 9 0 0
Popular vote 58,801 58,372 31,362
Percentage 35.52 35.26 18.94
 
Nominee Abraham Lincoln
Party Republican
Home state Illinois
Running mate Hannibal Hamlin
Electoral vote 0
Popular vote 17,028
Percentage 10.28
President before election

James Buchanan
Democratic

 Elected President

Abraham Lincoln
Republican

This article describes the United States presidential election, 1860, in Missouri.

Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President. Missouri voted for the Democratic candidate, Stephen A. Douglas.

Presidential Candidate Running Mate Party Electoral Vote (EV) Popular Vote (PV)
Stephen A. Douglas Herschel Johnson Democratic 9[1] 58,801 35.52%
John Bell Edward Everett Constitutional Union 0 58,372 35.26%
John Breckenridge Joseph Lane Southern Democrat 0 31,362 18.94%
Abraham Lincoln Hannibal Hamlin Republican 0 17,028 10.28%

Statewide winner in bold.


References

  1. ↑ 1860 Presidential General Election Results - Missouri
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