Elkhart Township, Noble County, Indiana

Elkhart Township
Township

Location in Noble County
Coordinates: 41°28′53″N 85°28′43″W / 41.48139°N 85.47861°W / 41.48139; -85.47861Coordinates: 41°28′53″N 85°28′43″W / 41.48139°N 85.47861°W / 41.48139; -85.47861
Country  United States
State  Indiana
County Noble
Government
  Type Indiana township
Area
  Total 35.9 sq mi (93 km2)
  Land 35.38 sq mi (91.6 km2)
  Water 0.52 sq mi (1.3 km2)  1.45%
Elevation 892 ft (272 m)
Population (2010)
  Total 2,065
  Density 58.4/sq mi (22.5/km2)
ZIP codes 46571, 46767, 46784, 46794
GNIS feature ID 0453276

Elkhart Township is one of thirteen townships in Noble County, Indiana, United States. As of the 2010 census, its population was 2,065 and it contained 826 housing units.[1]

Geography

According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.38 square miles (91.6 km2) (or 98.55%) is land and 0.52 square miles (1.3 km2) (or 1.45%) is water.[1]

Unincorporated towns

Cemeteries

The township contains Lower Cemetery.

Major highways

Lakes

School districts

Political districts

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.

External links

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