United States presidential election in Nebraska, 1992

United States presidential election in Nebraska, 1992

November 3, 1992

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 5 0 0 Popular vote 344,346 217,344 174,687 Percentage 46.6% 29.4% 23.6%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

Elections in Nebraska
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The 1992 United States presidential election in Nebraska took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Nebraska was won by incumbent President George H.W. Bush (R-Texas) with 46.58% of the popular vote over Governor Bill Clinton (D-Arkansas) with 29.40%. Businessman Ross Perot (I-Texas) finished in third with 23.63% of the popular vote.^[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.^[2]

Results

References

State results of the 1992 U.S. presidential election
Candidates	Bill Clinton George H. W. Bush Ross Perot Lyndon LaRouche Full list
General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates
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Other 1992 elections	House Senate Gubernatorial