Harford, New York

Not to be confused with Hartford, New York.
Harford, New York
Town
Harford

Location within the state of New York

Coordinates: 42°26′18″N 76°11′59″W / 42.43833°N 76.19972°W / 42.43833; -76.19972
Country United States
State New York
County Cortland
Government
  Type Town Council
  Town Supervisor Raymond Marsh (D, R)
  Town Council
Area
  Total 24.17 sq mi (62.61 km2)
  Land 24.15 sq mi (62.55 km2)
  Water 0.02 sq mi (0.06 km2)
Elevation 1,552 ft (473 m)
Population (2010)
  Total 943
  Density 39/sq mi (15.1/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
ZIP code 13784
Area code(s) 607
FIPS code 36-32160
GNIS feature ID 0979047

Harford is a town in Cortland County, New York, United States. The population was 943 at the 2010 census.[1] Harford is in the southwest corner of Cortland County and is south of Cortland.

History

Harford was in the former Central New York Military Tract in a tract called "Virgil". The area was first settled around 1803.

The town was established in 1845 from part of the town of Virgil. By 1865, the population was 888.

In the 1970s, Cornell University bought extensive tracts of land for livestock research.

Geography

According to the United States Census Bureau, the town has a total area of 24.2 square miles (62.6 km2), of which 0.02 square miles (0.06 km2), or 0.09%, is water.[1]

The west town line is the border of Tompkins County, and the south town line is the border of Tioga County.

New York State Route 38 runs diagonally across the southwest corner of Harford. New York State Route 200 intersects New York State Route 221 east of Harford village.

The East Branch of Owego Creek, part of the Susquehanna River watershed, flows southward through the town. The northwest corner of the town drains northward to Virgil Creek, a tributary of Fall Creek, which flows west to Cayuga Lake in Ithaca and is thus part of the Lake Ontario watershed. Because of the steep hills in the north of the town, the larger settlements are in the south part.

Demographics

Historical population
Census Pop.
1850926
18609462.2%
18709975.4%
18801,0343.7%
1890861−16.7%
1900753−12.5%
1910623−17.3%
1920553−11.2%
19305540.2%
19405723.2%
19505842.1%
19606358.7%
197074817.8%
198085514.3%
19908863.6%
20009203.8%
20109432.5%
Est. 2014942[2]−0.1%
U.S. Decennial Census[3]

As of the census[4] of 2000, there were 920 people, 341 households, and 246 families residing in the town. The population density was 38.1 people per square mile (14.7/km²). There were 363 housing units at an average density of 15.0 per square mile (5.8/km²). The racial makeup of the town was 97.72% White, 1.30% African American, 0.22% Native American, 0.11% Asian, and 0.65% from two or more races. Hispanic or Latino of any race were 0.22% of the population.

There were 341 households out of which 36.1% had children under the age of 18 living with them, 59.8% were married couples living together, 8.2% had a female householder with no husband present, and 27.6% were non-families. 21.1% of all households were made up of individuals and 7.9% had someone living alone who was 65 years of age or older. The average household size was 2.70 and the average family size was 3.15.

In the town the population was spread out with 30.0% under the age of 18, 6.1% from 18 to 24, 27.5% from 25 to 44, 25.0% from 45 to 64, and 11.4% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 99.6 males. For every 100 females age 18 and over, there were 100.6 males.

The median income for a household in the town was $33,750, and the median income for a family was $41,111. Males had a median income of $29,044 versus $20,673 for females. The per capita income for the town was $16,346. About 6.0% of families and 8.3% of the population were below the poverty line, including 4.5% of those under age 18 and 6.9% of those age 65 or over.

Communities and locations in Harford

References

Coordinates: 42°25′34″N 76°13′36″W / 42.42611°N 76.22667°W / 42.42611; -76.22667

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